f(x+4)=x^2+5x-5

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Solution for f(x+4)=x^2+5x-5 equation: 


Simplifying
f(x + 4) = x2 + 5x + -5

Reorder the terms:
f(4 + x) = x2 + 5x + -5
(4 * f + x * f) = x2 + 5x + -5
(4f + fx) = x2 + 5x + -5

Reorder the terms:
4f + fx = -5 + 5x + x2

Solving
4f + fx = -5 + 5x + x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
5 + 4f + fx + -5x + -1x2 = -5 + 5x + x2 + 5 + -5x + -1x2

Reorder the terms:
5 + 4f + fx + -5x + -1x2 = -5 + 5 + 5x + -5x + x2 + -1x2

Combine like terms: -5 + 5 = 0
5 + 4f + fx + -5x + -1x2 = 0 + 5x + -5x + x2 + -1x2
5 + 4f + fx + -5x + -1x2 = 5x + -5x + x2 + -1x2

Combine like terms: 5x + -5x = 0
5 + 4f + fx + -5x + -1x2 = 0 + x2 + -1x2
5 + 4f + fx + -5x + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
5 + 4f + fx + -5x + -1x2 = 0

The solution to this equation could not be determined.

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